-x^2+4.5x+2=0

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Solution for -x^2+4.5x+2=0 equation:



-x^2+4.5x+2=0
We add all the numbers together, and all the variables
-1x^2+4.5x+2=0
a = -1; b = 4.5; c = +2;
Δ = b2-4ac
Δ = 4.52-4·(-1)·2
Δ = 28.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{28.25}}{2*-1}=\frac{-4.5-\sqrt{28.25}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{28.25}}{2*-1}=\frac{-4.5+\sqrt{28.25}}{-2} $

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